postgresql中，将字符串'1|23|456'按'|'拆分为3行 1 23 456 以下哪些选项是可行的？ 答案: 1. select unnest(regexp_matches('1|23|456','\d+','g')) ; 2. select regexp_split_to_table('1|23|456','\|'); 3. select unnest(regexp_split_to_array('1|23|456','\|')); 4. select split_part('1|23|456','|',i+1) from generate_series(0,length('1|23|456')-length(replace('1|23|456','|',''))) as i;