
在Oracle中,和“消除”相关的查询转换有哪些?
(一)排序消除
1LHR@orclasm > SELECT COUNT(1) FROM ( SELECT T.EMPNO FROM SCOTT.EMP T ORDER BY T.EMPNO);
2
3 COUNT(1)
4----------
5 14
6
7
8Execution Plan
9----------------------------------------------------------
10Plan hash value: 96606410
11
12-----------------------------------------------------------------------------
13| Id | Operation | Name | Rows | Cost (%CPU)| Time |
14-----------------------------------------------------------------------------
15| 0 | SELECT STATEMENT | | 1 | 1 (0)| 00:00:01 |
16| 1 | SORT AGGREGATE | | 1 | | |
17| 2 | INDEX FULL SCAN| IDX_FULL_EMP_LHR | 14 | 1 (0)| 00:00:01 |
18-----------------------------------------------------------------------------
19
20
21Statistics
22----------------------------------------------------------
23 47 recursive calls
24 5 db block gets
25 1 consistent gets
26 0 physical reads
27 2616 redo size
28 526 bytes sent via SQL*Net to client
29 519 bytes received via SQL*Net from client
30 2 SQL*Net roundtrips to/from client
31 0 sorts (memory)
32 0 sorts (disk)
33 1 rows processed
(二)去重消除
1CREATE TABLE T_QC_20170613_LHR AS SELECT * FROM DBA_USERS;
2
3LHR@orclasm > SELECT DISTINCT T.USERNAME FROM T_QC_20170613_LHR T;
4
5Execution Plan
6----------------------------------------------------------
7Plan hash value: 1708573004
8
9----------------------------------------------------------------------------------------
10| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
11----------------------------------------------------------------------------------------
12| 0 | SELECT STATEMENT | | 58 | 986 | 4 (25)| 00:00:01 |
13| 1 | HASH UNIQUE | | 58 | 986 | 4 (25)| 00:00:01 |
14| 2 | TABLE ACCESS FULL| T_QC_20170613_LHR | 58 | 986 | 3 (0)| 00:00:01 |
15----------------------------------------------------------------------------------------
16
17Note
18-----
19 - dynamic sampling used for this statement (level=2)
20
21
22Statistics
23----------------------------------------------------------
24 6 recursive calls
25 0 db block gets
26 9 consistent gets
27 1 physical reads
28 0 redo size
29 1710 bytes sent via SQL*Net to client
30 552 bytes received via SQL*Net from client
31 5 SQL*Net roundtrips to/from client
32 0 sorts (memory)
33 0 sorts (disk)
34 58 rows processed
35
36ALTER TABLE T_QC_20170613_LHR ADD PRIMARY KEY (USERNAME);
37
38LHR@orclasm > SELECT DISTINCT T.USERNAME FROM T_QC_20170613_LHR T;
39
40Execution Plan
41----------------------------------------------------------
42Plan hash value: 884813832
43
44---------------------------------------------------------------------------------
45| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
46---------------------------------------------------------------------------------
47| 0 | SELECT STATEMENT | | 58 | 986 | 1 (0)| 00:00:01 |
48| 1 | INDEX FULL SCAN | SYS_C0089569 | 58 | 986 | 1 (0)| 00:00:01 |
49---------------------------------------------------------------------------------
50
51Note
52-----
53 - dynamic sampling used for this statement (level=2)
54
55
56Statistics
57----------------------------------------------------------
58 79 recursive calls
59 28 db block gets
60 83 consistent gets
61 0 physical reads
62 0 redo size
63 1710 bytes sent via SQL*Net to client
64 552 bytes received via SQL*Net from client
65 5 SQL*Net roundtrips to/from client
66 6 sorts (memory)
67 0 sorts (disk)
68 58 rows processed
(三)表消除
1SELECT A.* FROM SCOTT.EMP A,SCOTT.DEPT B WHERE A.DEPTNO=B.DEPTNO;
2--------------------------------------------------------------------------
3| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
4--------------------------------------------------------------------------
5| 0 | SELECT STATEMENT | | 14 | 1218 | 3 (0)| 00:00:01 |
6|* 1 | TABLE ACCESS FULL| EMP | 14 | 1218 | 3 (0)| 00:00:01 |
7--------------------------------------------------------------------------
8
9Predicate Information (identified by operation id):
10---------------------------------------------------
11
12 1 - filter("A"."DEPTNO" IS NOT NULL)
(四)公共子表达式消除(Common Sub-expression Elimination,CSE)
1LHR@orclasm > SELECT * FROM SCOTT.EMP A,SCOTT.DEPT B WHERE ( A.DEPTNO=B.DEPTNO AND A.EMPNO<=7521) OR ( A.DEPTNO=B.DEPTNO AND A.EMPNO>=7782 );
2
3---------------------------------------------------------------------------
4| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
5---------------------------------------------------------------------------
6| 0 | SELECT STATEMENT | | 11 | 1287 | 7 (15)| 00:00:01 |
7|* 1 | HASH JOIN | | 11 | 1287 | 7 (15)| 00:00:01 |
8| 2 | TABLE ACCESS FULL| DEPT | 4 | 120 | 3 (0)| 00:00:01 |
9|* 3 | TABLE ACCESS FULL| EMP | 11 | 957 | 3 (0)| 00:00:01 |
10---------------------------------------------------------------------------
11
12Predicate Information (identified by operation id):
13---------------------------------------------------
14
15 1 - access("A"."DEPTNO"="B"."DEPTNO")
16 3 - filter("A"."EMPNO"<=7521 OR "A"."EMPNO">=7782)
17
18LHR@orclasm > ALTER SESSION SET "_ELIMINATE_COMMON_SUBEXPR"=FALSE;
19
20Session altered.
21
22LHR@orclasm > SELECT * FROM SCOTT.EMP A,SCOTT.DEPT B WHERE ( A.DEPTNO=B.DEPTNO AND A.EMPNO<=7521) OR ( A.DEPTNO=B.DEPTNO AND A.EMPNO>=7782 );
23
24---------------------------------------------------------------------------
25| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
26---------------------------------------------------------------------------
27| 0 | SELECT STATEMENT | | 1 | 117 | 10 (0)| 00:00:01 |
28| 1 | NESTED LOOPS | | 1 | 117 | 10 (0)| 00:00:01 |
29| 2 | TABLE ACCESS FULL| DEPT | 4 | 120 | 3 (0)| 00:00:01 |
30|* 3 | TABLE ACCESS FULL| EMP | 1 | 87 | 2 (0)| 00:00:01 |
31---------------------------------------------------------------------------
32
33Predicate Information (identified by operation id):
34---------------------------------------------------
35
36 3 - filter("A"."DEPTNO"="B"."DEPTNO" AND "A"."EMPNO"<=7521 OR
37 "A"."DEPTNO"="B"."DEPTNO" AND "A"."EMPNO">=7782)
本文选自《Oracle程序员面试笔试宝典》,作者:李华荣。

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最后修改时间:2020-01-10 18:17:34
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