
在Oracle中,降序索引和升序索引分别是什么?
对于升序索引(Ascending Indexes),数据库按升序排列的顺序存储数据。索引默认按照升序存储列值。默认情况下,字符数据按每个字节中包含的二进制值排序,数值数据按从小到大排序,日期数据从早到晚排序。
降序索引(Descending Indexes)将存储在一个特定的列或多列中的数据按降序排序。创建降序索引时使用DESC关键字,如下所示:
1CREATE INDEX IND_DESC ON TESTDESC(A DESC,B ASC);
需要注意的是,降序索引在DBA_INDEXES的INDEX_TYPE列表现为FUNCTION-BASED即函数索引,但是在DBA_IND_EXPRESSIONS不能体现其升序或降序,只能通过视图DBA_IND_COLUMNS的DESCEND列来查询,如下所示:
先创建表和索引:
1CREATE TABLE XT_DESC_LHR AS SELECT * FROM DBA_OBJECTS;
2CREATE INDEX IND_DESC_LHR ON XT_DESC_LHR(OBJECT_ID DESC,OBJECT_NAME ASC);
3CREATE INDEX IND_DESC_LHR2 ON XT_DESC_LHR(OBJECT_NAME DESC);
4CREATE INDEX IND_DESC_LHR3 ON XT_DESC_LHR(OBJECT_type ASC);
查询索引:
1SYS@orclasm > SELECT D.INDEX_NAME,D.INDEX_TYPE FROM DBA_INDEXES D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%';
2INDEX_NAME INDEX_TYPE
3------------------------------ ---------------------------
4IND_DESC_LHR FUNCTION-BASED NORMAL
5IND_DESC_LHR2 FUNCTION-BASED NORMAL
6IND_DESC_LHR3 NORMAL
7SYS@orclasm > SET LINE 9999
8SYS@orclasm > SELECT D.INDEX_NAME,D.COLUMN_EXPRESSION FROM DBA_IND_EXPRESSIONS D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%' ;
9INDEX_NAME COLUMN_EXPRESSION
10------------------------------ -------------------------
11IND_DESC_LHR "OBJECT_ID"
12IND_DESC_LHR2 "OBJECT_NAME"
13SYS@orclasm > COL COLUMN_NAME FORMAT A15
14SYS@orclasm > SELECT d.INDEX_NAME,d.COLUMN_NAME,d.COLUMN_POSITION,d.DESCEND FROM DBA_IND_COLUMNS D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%' ORDER BY d.INDEX_NAME,d.COLUMN_POSITION;
15INDEX_NAME COLUMN_NAME COLUMN_POSITION DESC
16------------------------------ --------------- --------------- ----
17IND_DESC_LHR SYS_NC00016$ 1 DESC
18IND_DESC_LHR OBJECT_NAME 2 ASC
19IND_DESC_LHR2 SYS_NC00017$ 1 DESC
20IND_DESC_LHR3 OBJECT_TYPE 1 ASC
21SYS@orclasm > SELECT COLUMN_NAME,DATA_TYPE,DATA_DEFAULT FROM DBA_TAB_COLS WHERE OWNER='LHR' AND TABLE_NAME='XT_DESC_LHR' AND COLUMN_NAME='SYS_NC00016$';
22COLUMN_NAME DATA_TYPE DATA_DEFAULT
23------------------------------ ---------------------- -----------------
24SYS_NC00016$ RAW "OBJECT_ID"
25LHR@orclasm > SELECT * FROM XT_DESC_LHR t WHERE t.object_name='LHR' AND T.OBJECT_ID=1 ORDER BY OBJECT_ID DESC,OBJECT_NAME ASC;
26no rows selected
27Execution Plan
28----------------------------------------------------------
29Plan hash value: 902722624
30--------------------------------------------------------------------------------------------
31| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
32--------------------------------------------------------------------------------------------
33| 0 | SELECT STATEMENT | | 8 | 1656 | 2 (0)| 00:00:01 |
34| 1 | TABLE ACCESS BY INDEX ROWID| XT_DESC_LHR | 8 | 1656 | 2 (0)| 00:00:01 |
35|* 2 | INDEX RANGE SCAN | IND_DESC_LHR | 1 | | 1 (0)| 00:00:01 |
36--------------------------------------------------------------------------------------------
37Predicate Information (identified by operation id):
38---------------------------------------------------
39 2 - access(SYS_OP_DESCEND("OBJECT_ID")=HEXTORAW('3EFDFF') AND
40 "T"."OBJECT_NAME"='LHR')
41 filter(SYS_OP_UNDESCEND(SYS_OP_DESCEND("OBJECT_ID"))=1)
42Note
43-----
44 - dynamic sampling used for this statement (level=2)
45Statistics
46----------------------------------------------------------
47 0 recursive calls
48 0 db block gets
49 2 consistent gets
50 0 physical reads
51 0 redo size
52 1343 bytes sent via SQL*Net to client
53 508 bytes received via SQL*Net from client
54 1 SQL*Net roundtrips to/from client
55 0 sorts (memory)
56 0 sorts (disk)
57 0 rows processed
本文选自《Oracle程序员面试笔试宝典》,作者:李华荣。

---------------优质麦课------------

详细内容可以添加麦老师微信或QQ私聊。

● 本文作者:小麦苗,只专注于数据库的技术,更注重技术的运用
● 作者博客地址:http://blog.itpub.net/26736162/abstract/1/
● 本系列题目来源于作者的学习笔记,部分整理自网络,若有侵权或不当之处还请谅解
● 版权所有,欢迎分享本文,转载请保留出处
● QQ:646634621 QQ群:618766405
● 提供OCP、OCM和高可用部分最实用的技能培训
● 题目解答若有不当之处,还望各位朋友批评指正,共同进步
长按下图识别二维码或微信扫描下图二维码来关注小麦苗的微信公众号:xiaomaimiaolhr,学习最实用的数据库技术。



文章转载自DB宝,如果涉嫌侵权,请发送邮件至:contact@modb.pro进行举报,并提供相关证据,一经查实,墨天轮将立刻删除相关内容。




