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Excel~VBA实现MD5加密

子不语博客 2022-01-03
3242

网络上关于这段代码的文章很多,但是注释及源码出处不详。这里我也没找到原始出处,只对代码做了简单的注释。

'VBA MD5 加密算法
'参考文档:http://www.faqs.org/rfcs/rfc1321.html
'参考文档:https://github.com/vieyahn2017/iBlog/issues/378
'MD5信息摘要算法(Message-Digest Algorithm)以512位分组来处理输入的信息,且每一分组又被划分为16个32位子分组,经过了一系列的处理后,算法的输出由四个32位分组组成,将这四个32位分组级联后将生成一个128位散列值。
'第一步:填充补齐数据。要求填充后信息的长度就为 N*512+448(bit),填充的方法是填充一个1和n个0。
'第二步:记录信息长度。用64位来存储填充前信息长度。这64位加在第一步结果的后面,这样信息长度就变为N*512+448+64=(N+1)*512位。
'第三步:初始化MD缓存器:用来保存中间变量和最终结果。分别是(A=(01234567)16,B=(89ABCDEF)16,C=(FEDCBA98)16,D=(76543210)16),在程序中则为:(A=0X67452301L,B=0XEFCDAB89L,C=0X98BADCFEL,D=0X10325476L)。
'第四步:四轮循环运算:循环的次数是分组的个数(N+1)。
'4.1、定义4个非线性函数F、G、H、I,对输入的报文运算以512位数据段为单位进行处理。
'4.2、对每个数据段都要进行4轮的逻辑处理,在4轮中分别使用4个不同的函数F、G、H、I。每一轮以ABCD和当前的512位的块为输入,处理后送入ABCD(128位)。

Private Const BITS_TO_A_BYTE = 8 '一个字节的比特数
Private Const BYTES_TO_A_WORD = 4 '一个单元的字节数
Private Const BITS_TO_A_WORD = 32 '一个单元的比特数

Private m_lOnBits(30)
Private m_l2Power(30)

'向左移位
Private Function LShift(lValue, iShiftBits)
If iShiftBits = 0 Then
LShift = lValue
Exit Function
ElseIf iShiftBits = 31 Then
If lValue And 1 Then
LShift = &H80000000
Else
LShift = 0
End If
Exit Function
ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
Err.Raise 6
End If

If (lValue And m_l2Power(31 - iShiftBits)) Then
LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * m_l2Power(iShiftBits)) Or &H80000000
Else
LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * m_l2Power(iShiftBits))
End If
End Function

'向右移位
Private Function RShift(lValue, iShiftBits)
If iShiftBits = 0 Then
RShift = lValue
Exit Function
ElseIf iShiftBits = 31 Then
If lValue And &H80000000 Then
RShift = 1
Else
RShift = 0
End If
Exit Function
ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
Err.Raise 6
End If

RShift = (lValue And &H7FFFFFFE) \ m_l2Power(iShiftBits)

If (lValue And &H80000000) Then
RShift = (RShift Or (&H40000000 \ m_l2Power(iShiftBits - 1)))
End If
End Function

'移动一定位数
Private Function RotateLeft(lValue, iShiftBits)
RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End Function

'累加函数
Private Function AddUnsigned(lX, lY)
Dim lX4
Dim lY4
Dim lX8
Dim lY8
Dim lResult

lX8 = lX And &H80000000
lY8 = lY And &H80000000
lX4 = lX And &H40000000
lY4 = lY And &H40000000

lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)

If lX4 And lY4 Then
lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
ElseIf lX4 Or lY4 Then
If lResult And &H40000000 Then
lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
Else
lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
End If
Else
lResult = lResult Xor lX8 Xor lY8
End If

AddUnsigned = lResult
End Function

'第四步:四轮循环运算
'定义4个非线性函数F、G、H、I,对输入的报文运算以512位数据段为单位进行处理。
'非线性函数md5_F # 第一种形式
Private Function md5_F(x, y, z)
md5_F = (x And y) Or ((Not x) And z)
End Function
'非线性函数md5_G # 第二种形式
Private Function md5_G(x, y, z)
md5_G = (x And z) Or (y And (Not z))
End Function
'非线性函数md5_H # 第三种形式
Private Function md5_H(x, y, z)
md5_H = (x Xor y Xor z)
End Function
'非线性函数md5_I # 第四种形式
Private Function md5_I(x, y, z)
md5_I = (y Xor (x Or (Not z)))
End Function

'第四步:四轮循环运算
'四个处理函数的参数均为 (a, b, c, d, M, S, K)
'a, b, c, d:初始化MD缓存器
'明文 M:即 x 表示第 x 组第 k + n 个 int 数,它是一个 32bits 的明文数据,跟 A/B/C/D 长度相同,也是一个 word 的大小。
'位移 S:即 s 表示令 X <<< s 表示通过将 X 向左循环移位(旋转)s 个位而获得的 32 位值。
'正弦函数表K:即 ac ,共有 64 个常量数值,每个数值长度 32bits。

'处理函数 md5_FF # 第一种形式:
Private Sub md5_FF(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_F(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub
'处理函数 md5_GG # 第二种形式:
Private Sub md5_GG(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_G(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub
'处理函数 md5_HH # 第三种形式:
Private Sub md5_HH(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_H(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub
'处理函数 md5_II # 第四种形式:
Private Sub md5_II(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_I(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub

'第一步:填充补齐数据
'第二步:记录信息长度
'最终以 512 位分组明文数据
Private Function ConvertToWordArray(sMessage)
Dim lMessageLength
Dim lNumberOfWords
Dim lWordArray()
Dim lBytePosition
Dim lByteCount
Dim lWordCount

Const MODULUS_BITS = 512
Const CONGRUENT_BITS = 448

lMessageLength = Len(sMessage)

lNumberOfWords = (((lMessageLength + ((MODULUS_BITS - CONGRUENT_BITS) \ BITS_TO_A_BYTE)) \ (MODULUS_BITS \ BITS_TO_A_BYTE)) + 1) * (MODULUS_BITS \ BITS_TO_A_WORD)
ReDim lWordArray(lNumberOfWords - 1)

lBytePosition = 0
lByteCount = 0
Do Until lByteCount >= lMessageLength
lWordCount = lByteCount \ BYTES_TO_A_WORD
lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE
lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(Asc(Mid(sMessage, lByteCount + 1, 1)), lBytePosition)
lByteCount = lByteCount + 1
Loop

lWordCount = lByteCount \ BYTES_TO_A_WORD
lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE

lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(&H80, lBytePosition)

lWordArray(lNumberOfWords - 2) = LShift(lMessageLength, 3)
lWordArray(lNumberOfWords - 1) = RShift(lMessageLength, 29)

ConvertToWordArray = lWordArray
End Function

'Word转成16进制
Private Function WordToHex(lValue)
Dim lByte
Dim lCount

For lCount = 0 To 3
lByte = RShift(lValue, lCount * BITS_TO_A_BYTE) And m_lOnBits(BITS_TO_A_BYTE - 1)
WordToHex = WordToHex & Right("0" & Hex(lByte), 2)
Next
End Function

'输出 MD5 加密后的结果
Public Function MD5(sMessage, iType)
m_lOnBits(0) = CLng(1)
m_lOnBits(1) = CLng(3)
m_lOnBits(2) = CLng(7)
m_lOnBits(3) = CLng(15)
m_lOnBits(4) = CLng(31)
m_lOnBits(5) = CLng(63)
m_lOnBits(6) = CLng(127)
m_lOnBits(7) = CLng(255)
m_lOnBits(8) = CLng(511)
m_lOnBits(9) = CLng(1023)
m_lOnBits(10) = CLng(2047)
m_lOnBits(11) = CLng(4095)
m_lOnBits(12) = CLng(8191)
m_lOnBits(13) = CLng(16383)
m_lOnBits(14) = CLng(32767)
m_lOnBits(15) = CLng(65535)
m_lOnBits(16) = CLng(131071)
m_lOnBits(17) = CLng(262143)
m_lOnBits(18) = CLng(524287)
m_lOnBits(19) = CLng(1048575)
m_lOnBits(20) = CLng(2097151)
m_lOnBits(21) = CLng(4194303)
m_lOnBits(22) = CLng(8388607)
m_lOnBits(23) = CLng(16777215)
m_lOnBits(24) = CLng(33554431)
m_lOnBits(25) = CLng(67108863)
m_lOnBits(26) = CLng(134217727)
m_lOnBits(27) = CLng(268435455)
m_lOnBits(28) = CLng(536870911)
m_lOnBits(29) = CLng(1073741823)
m_lOnBits(30) = CLng(2147483647)

m_l2Power(0) = CLng(1)
m_l2Power(1) = CLng(2)
m_l2Power(2) = CLng(4)
m_l2Power(3) = CLng(8)
m_l2Power(4) = CLng(16)
m_l2Power(5) = CLng(32)
m_l2Power(6) = CLng(64)
m_l2Power(7) = CLng(128)
m_l2Power(8) = CLng(256)
m_l2Power(9) = CLng(512)
m_l2Power(10) = CLng(1024)
m_l2Power(11) = CLng(2048)
m_l2Power(12) = CLng(4096)
m_l2Power(13) = CLng(8192)
m_l2Power(14) = CLng(16384)
m_l2Power(15) = CLng(32768)
m_l2Power(16) = CLng(65536)
m_l2Power(17) = CLng(131072)
m_l2Power(18) = CLng(262144)
m_l2Power(19) = CLng(524288)
m_l2Power(20) = CLng(1048576)
m_l2Power(21) = CLng(2097152)
m_l2Power(22) = CLng(4194304)
m_l2Power(23) = CLng(8388608)
m_l2Power(24) = CLng(16777216)
m_l2Power(25) = CLng(33554432)
m_l2Power(26) = CLng(67108864)
m_l2Power(27) = CLng(134217728)
m_l2Power(28) = CLng(268435456)
m_l2Power(29) = CLng(536870912)
m_l2Power(30) = CLng(1073741824)

Dim x
Dim k
Dim AA
Dim BB
Dim CC
Dim DD
Dim a
Dim b
Dim c
Dim d

'0~15次对应的移位数组 [7, 12, 17, 22]
Const S11 = 7
Const S12 = 12
Const S13 = 17
Const S14 = 22
'16~31次对应的移位数组 [5, 9, 14, 20]
Const S21 = 5
Const S22 = 9
Const S23 = 14
Const S24 = 20
'32~47次对应的移位数组 [4, 11, 16, 23]
Const S31 = 4
Const S32 = 11
Const S33 = 16
Const S34 = 23
'48~63次对应的移位数组 [6, 10, 15, 21]
Const S41 = 6
Const S42 = 10
Const S43 = 15
Const S44 = 21

'第一步:填充补齐数据
'第二步:记录信息长度
x = ConvertToWordArray(sMessage)

'第三步:初始化MD缓存器
a = &H67452301
b = &HEFCDAB89
c = &H98BADCFE
d = &H10325476

'第四步:四轮循环运算
For k = 0 To UBound(x) Step 16
AA = a
BB = b
CC = c
DD = d

'对每个数据段都要进行4轮的逻辑处理,在4轮中分别使用4个不同的函数F、G、H、I。每一轮以ABCD和当前的512位的块为输入,处理后送入ABCD(128位)。

'第一轮
md5_FF a, b, c, d, x(k + 0), S11, &HD76AA478
md5_FF d, a, b, c, x(k + 1), S12, &HE8C7B756
md5_FF c, d, a, b, x(k + 2), S13, &H242070DB
md5_FF b, c, d, a, x(k + 3), S14, &HC1BDCEEE
md5_FF a, b, c, d, x(k + 4), S11, &HF57C0FAF
md5_FF d, a, b, c, x(k + 5), S12, &H4787C62A
md5_FF c, d, a, b, x(k + 6), S13, &HA8304613
md5_FF b, c, d, a, x(k + 7), S14, &HFD469501
md5_FF a, b, c, d, x(k + 8), S11, &H698098D8
md5_FF d, a, b, c, x(k + 9), S12, &H8B44F7AF
md5_FF c, d, a, b, x(k + 10), S13, &HFFFF5BB1
md5_FF b, c, d, a, x(k + 11), S14, &H895CD7BE
md5_FF a, b, c, d, x(k + 12), S11, &H6B901122
md5_FF d, a, b, c, x(k + 13), S12, &HFD987193
md5_FF c, d, a, b, x(k + 14), S13, &HA679438E
md5_FF b, c, d, a, x(k + 15), S14, &H49B40821
'第二轮
md5_GG a, b, c, d, x(k + 1), S21, &HF61E2562
md5_GG d, a, b, c, x(k + 6), S22, &HC040B340
md5_GG c, d, a, b, x(k + 11), S23, &H265E5A51
md5_GG b, c, d, a, x(k + 0), S24, &HE9B6C7AA
md5_GG a, b, c, d, x(k + 5), S21, &HD62F105D
md5_GG d, a, b, c, x(k + 10), S22, &H2441453
md5_GG c, d, a, b, x(k + 15), S23, &HD8A1E681
md5_GG b, c, d, a, x(k + 4), S24, &HE7D3FBC8
md5_GG a, b, c, d, x(k + 9), S21, &H21E1CDE6
md5_GG d, a, b, c, x(k + 14), S22, &HC33707D6
md5_GG c, d, a, b, x(k + 3), S23, &HF4D50D87
md5_GG b, c, d, a, x(k + 8), S24, &H455A14ED
md5_GG a, b, c, d, x(k + 13), S21, &HA9E3E905
md5_GG d, a, b, c, x(k + 2), S22, &HFCEFA3F8
md5_GG c, d, a, b, x(k + 7), S23, &H676F02D9
md5_GG b, c, d, a, x(k + 12), S24, &H8D2A4C8A
'第三轮
md5_HH a, b, c, d, x(k + 5), S31, &HFFFA3942
md5_HH d, a, b, c, x(k + 8), S32, &H8771F681
md5_HH c, d, a, b, x(k + 11), S33, &H6D9D6122
md5_HH b, c, d, a, x(k + 14), S34, &HFDE5380C
md5_HH a, b, c, d, x(k + 1), S31, &HA4BEEA44
md5_HH d, a, b, c, x(k + 4), S32, &H4BDECFA9
md5_HH c, d, a, b, x(k + 7), S33, &HF6BB4B60
md5_HH b, c, d, a, x(k + 10), S34, &HBEBFBC70
md5_HH a, b, c, d, x(k + 13), S31, &H289B7EC6
md5_HH d, a, b, c, x(k + 0), S32, &HEAA127FA
md5_HH c, d, a, b, x(k + 3), S33, &HD4EF3085
md5_HH b, c, d, a, x(k + 6), S34, &H4881D05
md5_HH a, b, c, d, x(k + 9), S31, &HD9D4D039
md5_HH d, a, b, c, x(k + 12), S32, &HE6DB99E5
md5_HH c, d, a, b, x(k + 15), S33, &H1FA27CF8
md5_HH b, c, d, a, x(k + 2), S34, &HC4AC5665
'第四轮
md5_II a, b, c, d, x(k + 0), S41, &HF4292244
md5_II d, a, b, c, x(k + 7), S42, &H432AFF97
md5_II c, d, a, b, x(k + 14), S43, &HAB9423A7
md5_II b, c, d, a, x(k + 5), S44, &HFC93A039
md5_II a, b, c, d, x(k + 12), S41, &H655B59C3
md5_II d, a, b, c, x(k + 3), S42, &H8F0CCC92
md5_II c, d, a, b, x(k + 10), S43, &HFFEFF47D
md5_II b, c, d, a, x(k + 1), S44, &H85845DD1
md5_II a, b, c, d, x(k + 8), S41, &H6FA87E4F
md5_II d, a, b, c, x(k + 15), S42, &HFE2CE6E0
md5_II c, d, a, b, x(k + 6), S43, &HA3014314
md5_II b, c, d, a, x(k + 13), S44, &H4E0811A1
md5_II a, b, c, d, x(k + 4), S41, &HF7537E82
md5_II d, a, b, c, x(k + 11), S42, &HBD3AF235
md5_II c, d, a, b, x(k + 2), S43, &H2AD7D2BB
md5_II b, c, d, a, x(k + 9), S44, &HEB86D391

a = AddUnsigned(a, AA)
b = AddUnsigned(b, BB)
c = AddUnsigned(c, CC)
d = AddUnsigned(d, DD)
Next

If iType = 32 Then
MD5 = LCase(WordToHex(a) & WordToHex(b) & WordToHex(c) & WordToHex(d))
Else
MD5 = LCase(WordToHex(b) & WordToHex(c))
End If
End Function

使用方法:

在 Excel 中新建一个模块,将代码复制进去,然后使用 MD5(strMessage, intType) 生成加密后的字符串即可。

  • strMsg:需要加密的明文

  • intType:加密的类型,16位或32位

参考文档:

  • http://www.faqs.org/rfcs/rfc1321.html

  • https://github.com/vieyahn2017/iBlog/issues/378


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