基于mysql的SQLadvisor工具一次优化尝试
使用方式:
1> 安装SQLAdvisor
[root@SQLAdvisor ~]# getenforceDisabled[root@SQLAdvisor ~]# yum -y install cmake libaio-devel libffi-devel glib2 glib2-devel
2> 配置Percona56 yum源;
$ yum install http://www.percona.com/downloads/percona-release/redhat/0.1-3/percona-release-0.1-3.noarch.rpm
安装Percona-Server-shared-56;
$ yum install Percona-Server-shared-56
3> 查看版本,测试是否安装成功。
[root@xjfw3 ~]# cmake --versioncmake version 3.10.0-rc4CMake suite maintained and supported by Kitware (kitware.com/cmake).
4> 建立软连接
[root@SQLAdvisor ~]# ln -s usr/lib64/libperconaserverclient_r.so.18 usr/lib64/libperconaserverclient_r.so
5> 编译依赖项sqlparser
[root@SQLAdvisor ~]# cd SQLAdvisor/[root@SQLAdvisor SQLAdvisor]# cmake -DBUILD_CONFIG=mysql_release -DCMAKE_BUILD_TYPE=debug -DCMAKE_INSTALL_PREFIX=/usr/local/sqlparser ./[root@SQLAdvisor SQLAdvisor]# make && make install
6> 安装SQLAdvisor
[root@SQLAdvisor SQLAdvisor]# cd sqladvisor/[root@SQLAdvisor sqladvisor]# cmake -DCMAKE_BUILD_TYPE=debug ./[root@SQLAdvisor sqladvisor]# make[root@SQLAdvisor sqladvisor]# ./sqladvisor --help
####################测试环境下的一次测试#######################
mysql> create database test1 character set utf8mb4;Query OK, 1 row affected (0.00 sec)mysql> create table user(-> id INT PRIMARY KEY AUTO_INCREMENT,-> name VARCHAR(64) NOT NULL,-> age int,-> sex int-> )ENGINE=INNODB DEFAULT CHARSET=utf8mb4;Query OK, 0 rows affected (0.13 sec)mysql> desc user;+-------+-------------+------+-----+---------+----------------+| Field | Type | Null | Key | Default | Extra |+-------+-------------+------+-----+---------+----------------+| id | int(11) | NO | PRI | NULL | auto_increment || name | varchar(64) | NO | | NULL | || age | int(11) | YES | | NULL | || sex | int(11) | YES | | NULL | |+-------+-------------+------+-----+---------+----------------+4 rows in set (0.01 sec)* 生成测试数据mysql> insert into user(name,age, sex) select 'lisea', 25, 1;Query OK, 1 row affected (0.01 sec)Records: 1 Duplicates: 0 Warnings: 0生产测试数据insert into user(name,age, sex) select concat(name, '1'), age+1, sex+1 from user;insert into user(name,age, sex) select concat(name, '2'), age+2, sex from user;insert into user(name,age, sex) select concat(name, '3'), age+2, sex from user;insert into user(name,age, sex) select concat(name, '10'), age+2, sex from user;insert into user(name,age, sex) select concat(name, '11'), age+4, sex from user;--执行两次结果[mysql@mysql sqladvisor]$ ./sqladvisor -h 192.168.226.131 -P 16063 -u root -p '6yhn^YHN' -d test1 -q "select * from user where name = 'lisea'" -v 12019-10-24 07:36:20 35965 [Note] 第1步: 对SQL解析优化之后得到的SQL:select `*` AS `*` from `test1`.`user` where (`name` = 'lisea')2019-10-24 07:36:20 35965 [Note] 第2步:开始解析where中的条件:(`name` = 'lisea')2019-10-24 07:36:20 35965 [Note] show index from user2019-10-24 07:36:20 35965 [Note] show table status like 'user'2019-10-24 07:36:20 35965 [Note] select count(*) from ( select `name` from `user` FORCE INDEX( PRIMARY ) order by id DESC limit 10000) `user` where (`name` = 'lisea')2019-10-24 07:36:20 35965 [Note] 第3步:表user的行数:1045485,limit行数:10000,得到where条件中(`name` = 'lisea')的选择度:100002019-10-24 07:36:20 35965 [Note] 第4步:开始验证 字段name是不是主键。表名:user2019-10-24 07:36:20 35965 [Note] show index from user where Key_name = 'PRIMARY' and Column_name ='name' and Seq_in_index = 12019-10-24 07:36:20 35965 [Note] 第5步:字段name不是主键。表名:user2019-10-24 07:36:20 35965 [Note] 第6步:开始验证 字段name是不是主键。表名:user2019-10-24 07:36:20 35965 [Note] show index from user where Key_name = 'PRIMARY' and Column_name ='name' and Seq_in_index = 12019-10-24 07:36:20 35965 [Note] 第7步:字段name不是主键。表名:user2019-10-24 07:36:20 35965 [Note] 第8步:开始验证表中是否已存在相关索引。表名:user, 字段名:name, 在索引中的位置:12019-10-24 07:36:20 35965 [Note] show index from user where Column_name ='name' and Seq_in_index =12019-10-24 07:36:20 35965 [Note] 第9步:开始输出表user索引优化建议:2019-10-24 07:36:20 35965 [Note] Create_Index_SQL:alter table user add index idx_name(name)2019-10-24 07:36:20 35965 [Note] 第10步: SQLAdvisor结束!也可配置文件传参调用[root@SQLAdvisor sqladvisor]# cat sql.cnf[sqladvisor]username=rootpassword=123host=127.0.0.1port=3306dbname=test1sqls=select * from user where name = 'lisea'[root@SQLAdvisor sqladvisor]# ./sqladvisor -f sql.cnf -v 1
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