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【牛客刷题-SQL大厂面试真题】NO1.某音短视频

原创 IT邦德 2022-07-31
581

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体系化学习SQL,请到牛客经典高频面试题库,参加实训,提高你的SQL技能吧~

https://www.nowcoder.com/link/pc_csdncpt_itbd_sql

文章目录

前言

SQL每个人都要用,但是用来衡量产出的并不是SQL本身,你需要用这个工具,去创造其它的价值。

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🐴 SQL1 各个视频的平均完播率

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:30', 0, 1, 1, null), (102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:24', 0, 0, 1, null), (103, 2001, '2021-10-01 11:00:00', '2021-10-01 11:00:34', 0, 1, 0, 1732526), (101, 2002, '2021-09-01 10:00:00', '2021-09-01 10:00:42', 1, 0, 1, null), (102, 2002, '2021-10-01 11:00:00', '2021-10-01 11:00:30', 1, 0, 1, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '影视', 30, '2021-01-01 7:00:00'), (2002, 901, '美食', 60, '2021-01-01 7:00:00'), (2003, 902, '旅游', 90, '2021-01-01 7:00:00');

📖 需求

问题:计算2021年里有播放记录的每个视频的完播率(结果保留三位小数),并按完播率降序排序 注:视频完播率是指完成播放次数占总播放次数的比例。简单起见, 结束观看时间与开始播放时间的差>=视频时长时,视为完成播放。

🍌🍌 答案

select a.video_id, round(sum(case when timestampdiff(second,b.start_time,b.end_time)>=a.duration then 1 else 0 end)/count(b.uid),3) as avg_com_play_rate from tb_video_info a join tb_user_video_log b on a.video_id=b.video_id where YEAR(b.start_time) = 2021 group by a.video_id order by avg_com_play_rate desc

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🐴 SQL2 平均播放进度大于60%的视频类别

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:30', 0, 1, 1, null), (102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:21', 0, 0, 1, null), (103, 2001, '2021-10-01 11:00:50', '2021-10-01 11:01:20', 0, 1, 0, 1732526), (102, 2002, '2021-10-01 11:00:00', '2021-10-01 11:00:30', 1, 0, 1, null), (103, 2002, '2021-10-01 10:59:05', '2021-10-01 11:00:05', 1, 0, 1, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '影视', 30, '2021-01-01 7:00:00'), (2002, 901, '美食', 60, '2021-01-01 7:00:00'), (2003, 902, '旅游', 90, '2020-01-01 7:00:00');

📖 需求

问题:计算各类视频的平均播放进度,将进度大于60%的类别输出。 注: 播放进度=播放时长÷视频时长*100%,当播放时长大于视频时长时,播放进度均记为100%。 结果保留两位小数,并按播放进度倒序排序。

🍌🍌 答案

select tag, concat( ROUND( avg( if( timestampdiff(second,start_time,end_time)>=duration, 1,timestampdiff(second,start_time,end_time)/duration ) )*100 ,2) ,'%') avg_play_progress from tb_user_video_log a join tb_video_info b on a.video_id=b.video_id group by b.tag having avg( if( timestampdiff(second,start_time,end_time)>=duration, 1,timestampdiff(second,start_time,end_time)/duration ) )>0.6 order by avg_play_progress desc

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🐴 SQL3 每类视频近一个月的转发量/率

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:20', 0, 1, 1, null) ,(102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:15', 0, 0, 1, null) ,(103, 2001, '2021-10-01 11:00:50', '2021-10-01 11:01:15', 0, 1, 0, 1732526) ,(102, 2002, '2021-09-10 11:00:00', '2021-09-10 11:00:30', 1, 0, 1, null) ,(103, 2002, '2021-10-01 10:59:05', '2021-10-01 11:00:05', 1, 0, 0, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '影视', 30, '2021-01-01 7:00:00') ,(2002, 901, '美食', 60, '2021-01-01 7:00:00') ,(2003, 902, '旅游', 90, '2020-01-01 7:00:00');

📖 需求

问题:统计在有用户互动的最近一个月(按包含当天在内的近30天算, 比如10月31日的近30天为10.2~10.31之间的数据)中,每类视频的转发量和转发率(保留3位小数)。 注:转发率=转发量÷播放量。结果按转发率降序排序。

🍌🍌 答案

select b.tag, sum(if_retweet) retweet_cnt, round(sum(if_retweet)/count(1),3) retweet_rate from tb_user_video_log a left join tb_video_info b on a.video_id = b.video_id where DATEDIFF(DATE((select max(start_time) from tb_user_video_log)) , DATE(start_time)) <= 29 group by b.tag order by 2 desc

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🐴 SQL4 每个创作者每月的涨粉率及截止当前的总粉丝量

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-09-01 10:00:00', '2021-09-01 10:00:20', 0, 1, 1, null) ,(105, 2002, '2021-09-10 11:00:00', '2021-09-10 11:00:30', 1, 0, 1, null) ,(101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:20', 1, 1, 1, null) ,(102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:15', 0, 0, 1, null) ,(103, 2001, '2021-10-01 11:00:50', '2021-10-01 11:01:15', 1, 1, 0, 1732526) ,(106, 2002, '2021-10-01 10:59:05', '2021-10-01 11:00:05', 2, 0, 0, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '影视', 30, '2021-01-01 7:00:00') ,(2002, 901, '影视', 60, '2021-01-01 7:00:00') ,(2003, 902, '旅游', 90, '2020-01-01 7:00:00') ,(2004, 902, '美女', 90, '2020-01-01 8:00:00');

📖 需求

问题:计算2021年里每个创作者每月的涨粉率及截止当月的总粉丝量 注: 涨粉率=(加粉量 - 掉粉量) / 播放量。结果按创作者ID、总粉丝量升序排序。 if_follow-是否关注为1表示用户观看视频中关注了视频创作者, 为0表示此次互动前后关注状态未发生变化,为2表示本次观看过程中取消了关注。

🍌🍌 答案

SELECT B.AUTHOR AS AUTHOR,DATE_FORMAT(A.start_time,'%Y-%m') AS MONTH , ROUND((COUNT(CASE WHEN A.if_follow=1 THEN 1 END ) - COUNT(CASE WHEN A.if_follow=2 THEN 1 END ))/COUNT(1) ,3) AS FANS_GROWTH_RATE, sum(sum(case when A.if_follow = 1 then 1 when A.if_follow = 2 then -1 else 0 end) ) over (partition by B.author order by date_format(A.start_time,'%Y-%m')) fans_total FROM tb_user_video_log A LEFT JOIN tb_video_info B ON A.VIDEO_ID=B.video_id WHERE year(A.start_time)=2021 and year(A.end_time)=2021 GROUP BY B.AUTHOR,DATE_FORMAT(A.start_time,'%Y-%m') ORDER BY AUTHOR,fans_total

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🐴 SQL5 国庆期间每类视频点赞量和转发量

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-09-24 10:00:00', '2021-09-24 10:00:20', 1, 1, 0, null) ,(105, 2002, '2021-09-25 11:00:00', '2021-09-25 11:00:30', 0, 0, 1, null) ,(102, 2002, '2021-09-25 11:00:00', '2021-09-25 11:00:30', 1, 1, 1, null) ,(101, 2002, '2021-09-26 11:00:00', '2021-09-26 11:00:30', 1, 0, 1, null) ,(101, 2002, '2021-09-27 11:00:00', '2021-09-27 11:00:30', 1, 1, 0, null) ,(102, 2002, '2021-09-28 11:00:00', '2021-09-28 11:00:30', 1, 0, 1, null) ,(103, 2002, '2021-09-29 11:00:00', '2021-09-29 11:00:30', 1, 0, 1, null) ,(102, 2002, '2021-09-30 11:00:00', '2021-09-30 11:00:30', 1, 1, 1, null) ,(101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:20', 1, 1, 0, null) ,(102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:15', 0, 0, 1, null) ,(103, 2001, '2021-10-01 11:00:50', '2021-10-01 11:01:15', 1, 1, 0, 1732526) ,(106, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:05', 2, 0, 1, null) ,(107, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:05', 1, 0, 1, null) ,(108, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:05', 1, 1, 1, null) ,(109, 2002, '2021-10-03 10:59:05', '2021-10-03 11:00:05', 0, 1, 0, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '旅游', 30, '2020-01-01 7:00:00') ,(2002, 901, '旅游', 60, '2021-01-01 7:00:00') ,(2003, 902, '影视', 90, '2020-01-01 7:00:00') ,(2004, 902, '美女', 90, '2020-01-01 8:00:00');

📖 需求

问题:统计2021年国庆头3天每类视频每天的近一周总点赞量和一周内最大单天转发量, 结果按视频类别降序、日期升序排序。假设数据库中数据足够多, 至少每个类别下国庆头3天及之前一周的每天都有播放记录。

🍌🍌 答案

select t1.tag,t1.day,sum(t2.likes),max(t2.retweet) FROM (select t2.tag ,left(t1.start_time,10) day, sum(t1.if_like) as likes,sum(t1.if_retweet) as retweet from tb_user_video_log t1 left join tb_video_info t2 on t1.video_id=t2.video_id group by t2.tag,day) t1 left join (select t2.tag ,left(t1.start_time,10) day, sum(t1.if_like) as likes,sum(t1.if_retweet) as retweet from tb_user_video_log t1 left join tb_video_info t2 on t1.video_id=t2.video_id group by t2.tag,day) t2 on t1.tag=t2.tag where TIMESTAMPDIFF(day,t2.day,t1.day)<7 and TIMESTAMPDIFF(day,t2.day,t1.day)>=0 and t1.day in ("2021-10-01","2021-10-02","2021-10-03") group by t1.tag,t1.day

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🐴 SQL6 近一个月发布的视频中热度最高的top3视频

🚀 建表语句

DROP TABLE IF EXISTS tb_user_video_log, tb_video_info; CREATE TABLE tb_user_video_log ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', uid INT NOT NULL COMMENT '用户ID', video_id INT NOT NULL COMMENT '视频ID', start_time datetime COMMENT '开始观看时间', end_time datetime COMMENT '结束观看时间', if_follow TINYINT COMMENT '是否关注', if_like TINYINT COMMENT '是否点赞', if_retweet TINYINT COMMENT '是否转发', comment_id INT COMMENT '评论ID' ) CHARACTER SET utf8 COLLATE utf8_bin; CREATE TABLE tb_video_info ( id INT PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID', video_id INT UNIQUE NOT NULL COMMENT '视频ID', author INT NOT NULL COMMENT '创作者ID', tag VARCHAR(16) NOT NULL COMMENT '类别标签', duration INT NOT NULL COMMENT '视频时长(秒数)', release_time datetime NOT NULL COMMENT '发布时间' )CHARACTER SET utf8 COLLATE utf8_bin; INSERT INTO tb_user_video_log(uid, video_id, start_time, end_time, if_follow, if_like, if_retweet, comment_id) VALUES (101, 2001, '2021-09-24 10:00:00', '2021-09-24 10:00:30', 1, 1, 1, null) ,(101, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:31', 1, 1, 0, null) ,(102, 2001, '2021-10-01 10:00:00', '2021-10-01 10:00:35', 0, 0, 1, null) ,(103, 2001, '2021-10-03 11:00:50', '2021-10-03 11:01:35', 1, 1, 0, 1732526) ,(106, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:04', 2, 0, 1, null) ,(107, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:06', 1, 0, 0, null) ,(108, 2002, '2021-10-02 10:59:05', '2021-10-02 11:00:05', 1, 1, 1, null) ,(109, 2002, '2021-10-03 10:59:05', '2021-10-03 11:00:01', 0, 1, 0, null) ,(105, 2002, '2021-09-25 11:00:00', '2021-09-25 11:00:30', 1, 0, 1, null) ,(101, 2003, '2021-09-26 11:00:00', '2021-09-26 11:00:30', 1, 0, 0, null) ,(101, 2003, '2021-09-30 11:00:00', '2021-09-30 11:00:30', 1, 1, 0, null); INSERT INTO tb_video_info(video_id, author, tag, duration, release_time) VALUES (2001, 901, '旅游', 30, '2021-09-05 7:00:00') ,(2002, 901, '旅游', 60, '2021-09-05 7:00:00') ,(2003, 902, '影视', 90, '2021-09-05 7:00:00') ,(2004, 902, '影视', 90, '2021-09-05 8:00:00');

📖 需求

问题:找出近一个月发布的视频中热度最高的top3视频。 注: 热度=(a*视频完播率+b*点赞数+c*评论数+d*转发数)*新鲜度; 新鲜度=1/(最近无播放天数+1); 当前配置的参数a,b,c,d分别为100、5、3、2。 最近播放日期以end_time-结束观看时间为准,假设为T,则最近一个月按[T-29, T]闭区间统计。 结果中热度保留为整数,并按热度降序排序。

🍌🍌 答案

select t1.video_id ,round( ((sum(case when timestampdiff(second,start_time,end_time)>=duration then 1 else 0 end ))/count(*)*100 +sum(if_like)*5 +count(comment_id)*3 +sum(if_retweet)*2) * 1/(DATEDIFF((select date(max(end_time)) from tb_user_video_log), date(max(end_time)))+1) ) as hot_index from tb_user_video_log t1,tb_video_info t2 where t1.video_id=t2.video_id and DATEDIFF(DATE((SELECT MAX(end_time) FROM tb_user_video_log)), DATE(release_time)) <= 29 group by t1.video_id order by hot_index desc limiT 3

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