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MySQL UPDATE查询用于更新MySQL数据库中表中的现有记录。它可以用于同时更新一个或多个字段。并且可用于使用WHERE子句指定任何条件。

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UPDATE更新查询的基本语法是

Where Update
查询的实现:
让我们考虑下表“Data”,其中包含四列
“ID”,“FirstName”,“LastName”和“Age”。

要更新“Data”表中“ID”为201的人员的“Age”,我们可以使用以下代码:
使用过程方法更新查询:
<?php
$link
= mysqli_connect("localhost", "root", "", "Mydb");
if($link
=== false){
die("ERROR: Could not connect. "
. mysqli_connect_error());
}
$sql
= "UPDATE data SET Age='28' WHERE id=201";
if(mysqli_query($link, $sql)){
echo
"Record was updated successfully.";
} else
{
echo
"ERROR: Could not able to execute $sql. "
. mysqli_error($link);
}
mysqli_close($link);
?>
输出:更新后的表格


<?php
$mysqli
= new
mysqli("localhost", "root", "", "Mydb");
if($mysqli
=== false){
die("ERROR: Could not connect. "
. $mysqli->connect_error);
}
$sql
= "UPDATE data SET Age='28' WHERE id=201";
if($mysqli->query($sql) === true){
echo
"Records was updated successfully.";
} else{
echo
"ERROR: Could not able to execute $sql. "
. $mysqli->error;
}
$mysqli->close();
?>
<?php
try{
$pdo
= new
PDO("mysql:host=localhost;
dbname=Mydb", "root", "");
$pdo->setAttribute(PDO::ATTR_ERRMODE,
PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e){
die("ERROR: Could not connect. "
. $e->getMessage());
}
try{
$sql
= "UPDATE data SET Age='28' WHERE id=201";
$pdo->exec($sql);
echo
"Records was updated successfully.";
} catch(PDOException $e){
die("ERROR: Could not able to execute $sql. "
. $e->getMessage());
}
unset($pdo);
?>
本篇文章就是关于MySQL更新查询的介绍,希望对需要的朋友有所帮助!
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