分析函数
LAG
语法:
LAG(expr,n ,m) over(partition by expr order by expr)
功能:当前记录前面第n行记录expr列的值。
expr是列字段名称。
n是大于等于0的整数。
m可以为字段值,常量,表达式。
说明:
如果当前记录前面第n行expr列没有值,则返回m。
如果不带参数n,m,则查找当前记录前面一行记录expr列的值,没有则默认值为null。
示例:
返回staffs表中的员工2个月前的工资。
--删除staffs表。
DROP TABLE IF EXISTS staffs;
--创建staffs表。
CREATE TABLE staffs
(
staff_id NUMBER(6) not null,
first_name VARCHAR2(20),
last_name VARCHAR2(25),
email VARCHAR2(25),
phone_number VARCHAR2(20),
hire_date DATE,
employment_id VARCHAR2(10),
salary NUMBER(8,2),
commission_pct NUMBER(2,2),
manager_id NUMBER(6),
section_id NUMBER(4),
graduated_name VARCHAR2(60)
);
--加入数据。
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (198, 'Donald', 'OConnell', 'DOCONNEL', '650.507.9833', to_date('21-06-1999', 'dd-mm-yyyy'), 'SH_CLERK', 2200.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (198, 'Donald', 'OConnell', 'DOCONNEL', '650.507.9833', to_date('21-06-1999', 'dd-mm-yyyy'), 'SH_CLERK', 2400.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (198, 'Donald', 'OConnell', 'DOCONNEL', '650.507.9833', to_date('21-06-1999', 'dd-mm-yyyy'), 'SH_CLERK', 2600.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (199, 'Douglas', 'Grant', 'DGRANT', '650.507.9844', to_date('13-01-2000', 'dd-mm-yyyy'), 'SH_CLERK', 4000.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (199, 'Douglas', 'Grant', 'DGRANT', '650.507.9844', to_date('13-01-2000', 'dd-mm-yyyy'), 'SH_CLERK', 4200.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (199, 'Douglas', 'Grant', 'DGRANT', '650.507.9844', to_date('13-01-2000', 'dd-mm-yyyy'), 'SH_CLERK', 4400.00, null, 124, 50);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (105, 'David', 'Austin', 'DAUSTIN', '590.423.4569', to_date('25-06-1997', 'dd-mm-yyyy'), 'IT_PROG', 4400.00, null, 103, 60);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (105, 'David', 'Austin', 'DAUSTIN', '590.423.4569', to_date('25-06-1997', 'dd-mm-yyyy'), 'IT_PROG', 4600.00, null, 103, 60);
insert into staffs (staff_id, first_name, last_name, email, phone_number, hire_date, employment_id, salary, commission_pct, manager_id, section_id)
values (105, 'David', 'Austin', 'DAUSTIN', '590.423.4569', to_date('25-06-1997', 'dd-mm-yyyy'), 'IT_PROG', 4800.00, null, 103, 60);
--返回员工两个月前的工资。
select staff_ID, lag(salary, 2,null)over(partition by staff_ID order by staff_ID) from staffs;
105
105
105 4400
198
198
198 2200
199
199
199 4000
9 rows fetched.「喜欢这篇文章,您的关注和赞赏是给作者最好的鼓励」
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