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Oracle在相同值排序的情况下,会如何选择谁在前谁在后?
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Oracle在相同值排序的情况下,会如何选择谁在前谁在后?

Oracle在相同值排序的情况下,会如何选择谁在前谁在后?

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SQL> create table t1 (id number,name varchar2(10)); Table created. SQL> insert into t1 values(1,'a'); 1 row created. SQL> insert into t1 values(2,'a'); 1 row created. SQL> insert into t1 values(3,'a'); 1 row created. SQL> commit; SQL> select * from t1 order by name; ID NAME ---------- ---------- 1 a 3 a 2 a SQL> select * from t1 order by name; ID NAME ---------- ---------- 1 a 3 a 2 a SQL> select rownum,rowid,id,name from t1 order by name; ROWNUM ROWID ID NAME ---------- ------------------ ---------- ---------- 1 AABsyUAABAAAvShAAA 1 a 3 AABsyUAABAAAvShAAC 3 a 2 AABsyUAABAAAvShAAB 2 a SQL> select rownum,rowid,id,name from t1 order by rowid; ROWNUM ROWID ID NAME ---------- ------------------ ---------- ---------- 1 AABsyUAABAAAvShAAA 1 a 2 AABsyUAABAAAvShAAB 2 a 3 AABsyUAABAAAvShAAC 3 a SQL> insert into t1 values(4,'b'); 1 row created. SQL> commit; Commit complete. SQL> select rownum,rowid,id,name from t1 order by name; ROWNUM ROWID ID NAME ---------- ------------------ ---------- ---------- 1 AABsyUAABAAAvShAAA 1 a 2 AABsyUAABAAAvShAAB 2 a 3 AABsyUAABAAAvShAAC 3 a 4 AABsyUAABAAAvShAAD 4 b SQL> alter system flush shared_pool; System altered. SQL> select rownum,rowid,id,name from t1 order by name; ROWNUM ROWID ID NAME ---------- ------------------ ---------- ---------- 1 AABsyUAABAAAvShAAA 1 a 2 AABsyUAABAAAvShAAB 2 a 3 AABsyUAABAAAvShAAC 3 a 4 AABsyUAABAAAvShAAD 4 b SQL> delete from t1 where id =4; 1 row deleted. SQL> commit; Commit complete. SQL> alter system flush shared_pool; System altered. SQL> select rownum,rowid,id,name from t1 order by name; ROWNUM ROWID ID NAME ---------- ------------------ ---------- ---------- 1 AABsyUAABAAAvShAAA 1 a 3 AABsyUAABAAAvShAAC 3 a 2 AABsyUAABAAAvShAAB 2 a

确实很神奇

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2022-08-15
通过实验,在值都相同只有Name = a 时,是根据数据库读取的先后顺序,排序的。
薛晓刚

任何都相同的时候看物理地址了,早来的在先

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